5^(2x+1)/5^(3x-2)=25^(-2)

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Solution for 5^(2x+1)/5^(3x-2)=25^(-2) equation: 



5^(2x+1)/5^(3x-2)=25^(-2)

We move all terms to the left:

5^(2x+1)/5^(3x-2)-(25^(-2))=0



Domain of the equation: 5^(3x-2)!=0

x∈R



We add all the numbers together, and all the variables

5^(2x+1)/5^(3x-2)-0.0016=0

We multiply all the terms by the denominator


5^(2x+1)-(0.0016)*5^(3x-2)=0

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